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=(5Y^2)+1
We move all terms to the left:
-((5Y^2)+1)=0
We get rid of parentheses
-5Y^2-1=0
a = -5; b = 0; c = -1;
Δ = b2-4ac
Δ = 02-4·(-5)·(-1)
Δ = -20
Delta is less than zero, so there is no solution for the equation
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